Showing posts with label Quantum mechanics. Show all posts
Showing posts with label Quantum mechanics. Show all posts

Monday, June 8, 2009

Electric dipole-dipole interaction

Electric dipole-dipole interaction between f electron atoms


Estimate of electric dipole moment:

According to Yen et al.[1], the electric dipole moment can be estimated as:
 
p~e<r>Vc/D,

where e is the elctronic charge, <r>~10-10 m is the mean radius of the 4f electronic orbit, Vc~500 cm-1 is the characteristic crystal field splitting, and D~60000 cm-1 [2] is the energy separation between (4f)n and (4f)n-1(5d)' configuration.

Then p~1.3e-31 C.m

Then the dipole-dipole interaction is

W=\frac{ p_1 p_2}{4\pi \epsilon_0 R^3}


eq=W=\frac{ p_1 p_2}{4\pi \epsilon_0 R^3}

For example, if R=0.42 nm, we get

W=1.2 e-5 eV, or 0.01 meV.



[1]    W. M. Yen et al., Physical Review 140, 1188 (1965).
[2]    G. H. Dieke, and H. M. Crosswhite, Applied Optics 2, 675 (1963).

Thursday, May 21, 2009

From oscillator strength to spontaneo...

From oscillator strength to spontaneous decay rate:

Approach I


Using
quantum mechanics, one can derive the relation between the oscillator
strength calculated from the absorption coefficient and the transition
matrix element |x|2. And the spontaneous decay rate is also decided by the matrix element |x|2, therefore, one can find the decay rate from the absorption coefficient.





f=\frac{2m\omega}{\hbar}|x|^2



eq=<br />f=\frac{2m\omega}{\hbar}|x|^2



while spontaneous decay rate:
A=\frac{e\omega^3}{3\pi\hbar c^3\epsilon_0 n^2}|x|^2



eq=A=\frac{e\omega^3}{3\pi\hbar c^3\epsilon_0 n^2}|x|^2






Therefore,




\frac{A}{f}=\frac{\omega^2e^2}{6m\pi c^3\epsilon_0n^2}







eq=\frac{A}{f}=\frac{\omega^2e^2}{6m\pi c^3\epsilon_0n^2}




Approach II: Judd-Ofelt theory,


f=\frac{2m\omega}{\hbar}S



eq=f=\frac{2m\omega}{\hbar}S



A=\frac{\omega^3e^2n^2}{\hbar c^3\pi\epsilon_0}S



eq=A=\frac{\omega^3e^2n^2}{\hbar c^3\pi\epsilon_0}S



Therefore,

\frac{A}{f}=\frac{\omega^2e^2n^2}{2mc^3\pi\epsilon_0}






eq=\frac{A}{f}=\frac{\omega^2e^2n^2}{2mc^3\pi\epsilon_0}

One can see that, in two approaches, there is an factor of 3n^4.

I am not so sure why two are not the same, but at this moment I tend to believe the second approach because it is specialized just for this case.

Usage

In a real experiment, oscillator strength can be found using partial sum rule:
The dimensionless oscillator strength is:
f=\frac{2c}{N_e\hbar \pi \omega_p^2}\int_{E_2}^{E_1}n\alpha dE

eq=f=\frac{2c}{N_e\hbar \pi \omega_p^2}\int_{E_2}^{E_1}n\alpha dE

Here
\omega_p^2=\frac{e^2 \rho}{m\epsilon_0}





eq=\omega_p^2=\frac{e^2 \rho}{m\epsilon_0}

[Reference:]

Kumar G.A. et al, Journal of Luminescence vol. 99, p. 141-148 (2002)







Conservation of

Conservation of Σλi

Description:

For a Helbert space (wave function subspace) {φi} defined by the operator O whose eigenvalues are λi, corresponding to wavefunction  φi.

Simply from linear algebra,
Σλi is actually the trace of the operator matrix O, which is of course conserved, no matter what unitary transformation of the {φi} is taken to form new set of basis, say {ψi}.

To generalize this, Σλin, is also conserved, because On also defines the space.

Example:

For a 4f electron multiplet, say, Nd3+, 4I9/2, ΣJz,in is conserved and of course Σμz,in is conserved too because they differ only by a factor of gμB

Just to give a few numbers,

sqrt(3Σμz,i2/5)=

3.6 μB(theoretical value)
3.4, 3.5 and 3.8 from measurement on crystal field split 4I9/2 multiplet.

Saturday, July 26, 2008

Summary of 3d atomic orbitals





Symmetry
Orbitals
Free atom
E1
m=2,
Ψ3,2,2 = (1 / 81√(2π)) (Z/a)7/2 r2 e-Zr/3a sin2θ ei2φ
m=1,
Ψ3,2,1 = (√2 / 81√π) (Z/a)7/2 r2 e-Zr/3a sinθ cosθ e
m=0,
Ψ3,2,0 = (1 / 81√(6π)) (Z/a)7/2 r2 e-Zr/3a (3cos2θ -1)
m=-1,
Ψ3,2,-1 = (√2 / 81√π) (Z/a)7/2 r2 e-Zr/3a sinθ cosθ e-iφ
m=-2,
Ψ
3,2,-2 = (1 / 81√(2π)) (Z/a)7/2r2 e-Zr/3a sin2θ e-i2φ
Octahedral / TetrahedralOh / Td
E1 (eg)
x2-y2=(3,2,2)+(3,2,-2)
sin2θ cos2φ
z2=(3,2,0)
(3cos2θ-1)

E2 (t2g)
xy=(3,2,2)-(3,2,-2)
sin2θ sin2φ
yz=(3,2,1)-(3,2,-1)
sinθ cosθ sinφ
xz=(3,2,1)+(3,2,-1)
sinθ cosθ cosφ
Triangular bipyramid symmetry
E1
x2-y2,
xy

E2
xz, yz

E3
z2




Angular momentum operator:
Lz=(ħ/i)∂/φ

Monday, June 30, 2008

Confusing matrix elements

When we discuss about the matrix element of optical transition, we often can use either of the following ways:

1) H1=exE, where e is the electronic charge, E is the electric field
2) H1=epA/m, where p is the momentum of the electron and A is the vector potential.

Following approach 1):

transition rate:
W=|<φi|exE0f>|2 δ(Ei-Ef-
ħω)=e2E02|<φi|x|φf>|2δ(Ei-Ef-ħω)

Power:
P=
ħωe2E02|<φi|x|φf>|2δ(Ei-Ef-ħω)

Dielectric constant (imaginary part):
ε2=P/(ε0ωE02)=ħe20|<φi|x|φf>|2δ(Ei-Ef-ħω)

However, if we use the approach 2)

transition rate:
W=|<φi|
epA/mf>|2 δ(Ei-Ef-ħω)=(e/m)2A02|<φi|p|φf>|2δ(Ei-Ef-ħω)

Power:
P=
ħω(e/m)2A02|<φi|p|φf>|2δ(Ei-Ef-ħω)

Dielectric constant (imaginary part):
using the relation that E0=
iωA0
ε2=P/(ε0ωE02)=ħ(e/m)2/(ε0ω2)|<φi|p|φf>|2δ(Ei-Ef-ħω)

We can easily see that the
function ε2(ω) in the two cases are very different, which one is correct and why?

In all the books I read, approach 2) seems to be used, why?

Quantization of electromagnetic field:

Vector potential:

An(r)=sqrt(ħ/2ε0ω)(an+an)un(r)