Saturday, August 30, 2008

Low frequency dielectric constant


Starting from Lorentz model:

md2x/dt2+mΓdx/dt+mω02x=qE

which is the equation of motion for a bond electric charge q with mass m in an oscillating field E, where ω0 is the frequency of the Harmonic potential of the charge and Γ is the dampling parameter.

Take the oscillating form of x and E:

x=x0
e-iωt and
E=E0e-iωt

one get the solution:

x=q/m/(ω022-iΓω).

The the dielectric constant will be (notice that P=xq):

ε=1+P/(Eε0)=1+q2/mε0/(ω022-iΓω)

For a low frequency measurement ω0>>ω,which is valid for normal dielectric measurement because the lowest ω0 is normally at the 1012 Hz range.

In this case, we can ignore the high order term ω2,

ε=1+q2/mε0/(ω02-iΓω).

Imaginary part:


The imaginary part is

ε2=q2Γω/mε0/(ω04+Γ2ω2).

Experimentally, a maximum is always observed for the temperature dependence of ε2, here we can calculate the maximum by solving

dε2/dT=0.

Note that the only temperature dependent parameter is Γ.

Then one gets:

Γ=ω02/ω at dε2/dT=0.

Now let's look at the parameter Γ. It is a dampling parameter, which should be proportional to relaxation time τ, which satisfies the Arhenious relation:

τ=τ0eEa/(kBT)

where Ea is activation energy (or energy barrier to overcome the).

We can even define:

τ=Γ/ω02.

Then

τ0eEa/(kBT)=1/ω should give us the temprature where the maximum ε2 is, which is

Ea/(kBTmax)=-log(τ0ω).

Experimentally, fitting the the relation between Tmax and ω, one gets the activation energy Ea, which is what most paper shows.

Real part:

The real part dielectric constant is

ε1=q2ω02/mε0/(ω04+Γ2ω2).

One can see that it increases monotonic with temperature simply because of the temperature dependence of Γ.


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