Low frequency dielectric constant
Starting from Lorentz model:
md2x/dt2+mΓdx/dt+mω02x=qE
which is the equation of motion for a bond electric charge q with mass m in an oscillating field E, where ω0 is the frequency of the Harmonic potential of the charge and Γ is the dampling parameter.
Take the oscillating form of x and E:
x=x0e-iωt and
E=E0e-iωt
one get the solution:
x=q/m/(ω02-ω2-iΓω).
The the dielectric constant will be (notice that P=xq):
ε=1+P/(Eε0)=1+q2/mε0/(ω02-ω2-iΓω)
For a low frequency measurement ω0>>ω,which is valid for normal dielectric measurement because the lowest ω0 is normally at the 1012 Hz range.
In this case, we can ignore the high order term ω2,
ε=1+q2/mε0/(ω02-iΓω).
Imaginary part:
The imaginary part is
ε2=q2Γω/mε0/(ω04+Γ2ω2).
Experimentally, a maximum is always observed for the temperature dependence of ε2, here we can calculate the maximum by solving
dε2/dT=0.
Note that the only temperature dependent parameter is Γ.
Then one gets:
Γ=ω02/ω at dε2/dT=0.
Now let's look at the parameter Γ. It is a dampling parameter, which should be proportional to relaxation time τ, which satisfies the Arhenious relation:
τ=τ0eEa/(kBT)
where Ea is activation energy (or energy barrier to overcome the).
We can even define:
τ=Γ/ω02.
Then
τ0eEa/(kBT)=1/ω should give us the temprature where the maximum ε2 is, which is
Ea/(kBTmax)=-log(τ0ω).
Experimentally, fitting the the relation between Tmax and ω, one gets the activation energy Ea, which is what most paper shows.
Real part:
The real part dielectric constant isε1=q2ω02/mε0/(ω04+Γ2ω2).
One can see that it increases monotonic with temperature simply because of the temperature dependence of Γ.
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