Thursday, May 29, 2008

vibrational modes for WS2

We can solve the vibrational modes from the Hamiltonian of classical mechanics.

Assuming:

1) There is one spring constant k, and two kinds of masses: m for S and M for W.

2) The coordinates are (x1,y1) and (x2,y2) for S and (x3,y3) for W.

Using {x1,y1,x2,y2,x3,y3} as basis, we can get the matrix:


,






Mode set one:







Mode set two (translation):









Mode set three:

Monday, May 19, 2008

DC conductivity of metal

σ = nq2τ/m

where n is the density of carrier, q is the charge of the carriers, tau is the
τ time, m is the effective mass.

The temperature dependence of
σ comes from the temperature dependence of τ.

τ can be found from scattering theory. It turns out that

1/
τ ~ A2, where A is the amplitude of the vibration.

A2 ~ n, where n is the number of phonons.

As we know that <n>=1/(exp(h
ω/kBT)-1).

At hight T, <n> ~ T, which is the linear relation found for 1/
τ or σ.

At low T, we have to consider not only the number of vibrational modes excited, but also the scattering effect of these mode.

The former gives T-3 relation and the latter gives T2. So the total relation will be T-5.



Thursday, May 1, 2008

sum rule in SI


neff=
0ωσ1dω/(π/2*ωp2)

where
ωp2=e2/(V0*m*ε0), V0 is the volume for the unit cell.